16x^2+32x=80

Solution for 16x^2+32x=80 equation:

16x^2+32x=80

We move all terms to the left:

16x^2+32x-(80)=0

a = 16; b = 32; c = -80;
Δ = b2-4ac
Δ = 322-4·16·(-80)
Δ = 6144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6144}=\sqrt{1024*6}=\sqrt{1024}*\sqrt{6}=32\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32\sqrt{6}}{2*16}=\frac{-32-32\sqrt{6}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32\sqrt{6}}{2*16}=\frac{-32+32\sqrt{6}}{32}
$